G Suppose that we have a quadrature Qn using n+1 function evaluations that approximates the integral Z b a f(x)dx with the error Z b a f(x)dx − Qn(f) = a1 · sin(1/n) + a2 · (sin(1/n))2 + a3 · (sin(1/n))3 + . . . . Using Qn, Q2n and Q4n, perform 2 steps of Richardson’s extrapolation, i. e., write down the formula for the resulting method and express its error in terms of a power of 1/n.

The Order is (1/n^3).  

Step-by-step explanation:

Please see the attached file for details.

d

step-by-step explanation:

i used the pitagoras theoreme

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180