What is the equation of the line that passes through the points (-9, -3) and (9, 3)?

y= 1/3x

Step-by-step explanation:

1.Plug the points into the slope formula- m=y2-y1/x2-x1.

So M=3-(-3)/9-(-9)

2.Solve: M=6/18

3.Simplify: M=1/3

4.Input into y=Mx+b

  y=1/3x+b

The x and y won't be changed for this equation.

5.Plug in one of the points into the new equation

  For (9,3): 3=1/3*9+b so B=0 because 1/3*9=3 which is what we want.

5.5 Or you can do it by solving for b: b=3-(1/3)(9)=0

6. Therefore B=0

7. So the end equation is y=1/3x

step-by-step explanation:

quartic functions has x = –1 and x = –2 as its only two real zeroes:

f(x) = a(x+2)(x+1)   a: real number

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: