A component is assembled in a four-step process. The probability of making a defect in step 1 is 10%; in step 2, 20%; in step 3, 8%; and in step 4, 5%. What is the probability that the component will be defective?

0.37072

Step-by-step explanation:

Let A be the event that step 1 is defective (P(A) = 10%), B the event that step 2 is defective(P(B) = 20%), C the event that step 3 is defective (P(C) = 8%), D the event that step 4 is defective(P(D) = 5%). Let us suppose that the occurance of a failure at any step is indepent of the other steps.

Recall the following properties

And given A, B, C, D independent , then

REcall that if the a set of events A,B,C,D are independent, their complements are also indepent.

Since we are asked for the probability of a defective item, this means that at least one of the steps is defective. Then, we are asked for the following probability:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

2, 2, 2 or -4, 20, 29

step-by-step explanation:

there is two ways you can do it.