In a cyclic quadrilateral ABCD, AD is parallel to BC. The bisector
of <BAD meets BC at E and...
Mathematics, 08.04.2020 06:19 veritoburito
In a cyclic quadrilateral ABCD, AD is parallel to BC. The bisector
of <BAD meets BC at E and the circle at F. Prove that:
EF=FC ( BF - DF
Answers: 2
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