Picture included
What is the value of X for the picture

Given:

One secant is x+ 5 and 8

Other secant is x + 1 and 9

To find:

The value of x

Solution:

If two secant segments intersect outside a circle, then the product of one segment and its external segment is equal to the product of other segment and its external segment.

External segment = 8 + x + 5 = x + 13

Another external segment = 9 + x + 1 = x + 10

Subtract 90 from both sides.

Subtract 8x from both sides.

The value of x is 14.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

include a picture of the drawing in order for me to

step-by-step explanation: