Use completing the square to find the equation of the following circle in standard form.

3x^2 + 3y^2 - 12x + 36y - 48 = 0

Group of answer choices

(x - 4)^2 + (y + 12)^2 = 176

(x - 2)^2 + (y + 6)^2 = LaTeX: \sqrt{56} 56

(x - 2)^2 + (y + 6)^2 = 56

(x - 2)^2 + (y + 6)^2 = 16

(x + 2)^2 + (y - 6)^2 = 56