On a coordinate plane, triangle A B C is shown. Point A is at (3, 4), point B is at (negative 5, negative 2), and point C is at (5, negative 2). In the diagram, AB = 10 and AC = 2 StartRoot 10 EndRoot. What is the perimeter of △ABC? 10 units 10 + 2 StartRoot 10 EndRoot units 20 units 20 + 2 StartRoot 10 EndRoot units

The perimeter of Δ ABC is 20 + 2 units ⇒ Last answer

Step-by-step explanation:

The perimeter of any triangle is the sum of the lengths of its three sides

The formula of distance between two points is

In Δ ABC

∵ A = (3 , 4) , B = (-5 , -2) , C = (5 , -2)

∵ AB = 10 units

∵ AC = 2

- To find its perimeter find the length of BC

∵ = -5 and = -2

∵ = 5 and = -2

- By using the formula above

∴

∴

∴ BC = 10 units

To find the perimeter add the lengths of the three sides

∵ P = AB + BC + AC

∴ P = 10 + 10 + 2

- Add like terms

∴ P = 20 + 2

The perimeter of Δ ABC is 20 + 2 units

n

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)