On a coordinate plane, two parabolas open up. The solid-line parabola goes through (1, 3), has a vertex at (3, negative 1), and goes through (5, 3). The dashed-line parabola goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4).
Which best describes the transformation from the graph of f(x) = x2 to the graph of
f(x) = (x – 3)2 – 1?

left 3 units, down 1 unit
left 3 units, up 1 unit
right 3 units, down 1 unit
right 3 units, up 1 unit

if farmer matt works for 8 hours a day, how many days will it take him to completely plant 12 rows of crops? each batch of cookies needs 3/4 cups of sugar.

step-by-step explanation:

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.

its perfect good job honey

step-by-step explanation:

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