DUE VERY SOON HELP!

A regular octagon has an apothem of 14.1 yd and a side length of 11.7 yd. What is the area of the regular octagon? If necessary, round your answer to the nearest whole number.

A regular heptagon (7-sided figure) has an apothem of 21.8 m and a side length of 21 m. What is the area of the regular heptagon? If necessary, round your answer to 1 decimal place.

A regular pentagon has an apothem of 7.3 in. and a side length of 10.6 in. What is the area of the regular pentagon?

I thinks it's 193.313

Step-by-step explanation: Let’s take the pentagon with side length 11.7 yards and apothem length 14.1 yards

Area of pentagon is = 5/2 x s x a

= 5/2 x 11.7 x 214.1

=6262.425 square centimetres.

Example 2 : Find the area of a pentagon of side 11.7 yards and apothem length 14.1 yards ?

Solution :

Given,

s = 11.7 yds

a = 14.1 yds

Area of a pentagon

= 193.313 yds

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b