Write the measure -128 30’ 45’’ as a decimal to the nearest thousandth

-127.488°

Step-by-step explanation:

45" is 0.75 of 1', so -128° 30' 45" = -128° 30.75'

Next:  30.75' is 30.75/60 of 1°, and or -128° plus 0.5125 of 1°.

The final answer is found by adding 0.5125° to -128°:

 -128.0000°

 +   0.5125°

 -127.4875

To the nearest thousandths of a degree, that would be -127.488°

final answer is : )

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.