In a certain Algebra 2 class of 28 students, 16 of them play basketball and 15 of them
play baseball. There are 8 students who play neither sport. What is the probability
that a student chosen randomly from the class plays basketball or baseball?

step-by-step explanation:

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)