A moving helper company gave Mike these two quotes. Use a system of equations to

determine the hourly rates for loading/unloading and packing/unpacking.

4 hours of

loading/unloading

7 hours of

loading/unloading

Step-by-step explanation:

Here, the given table is MISSING.

The correct table for reference is attached.

Now, let us assume the hourly rates  of loading/unloading = $ m

Assume the hourly rates  of packing/unpacking = $ n

As given in the table:

3 hours of  loading/unloading + 2 hours of packing/unpacking costs = $480

⇒ 3 m +  2 n = 480

⇒ 2 n =  480 - 3 m   .... (1)

5 hours of  loading/unloading + 2 hours of packing/unpacking costs = $680

⇒ 5 m +  2 n = 680  

⇒ 2 n =  680 - 5 m  .... (2)

Now, solving for the values of m and n, we get:

480 - 3 m =  680 - 5 m

⇒ 5 m - 3 m = 680 - 480

⇒ 2 m = 200

or, m  = 100

Now,  2 n =  680 - 5 m  =  680 - 5 (100) = 180

⇒ n = 90

Hence, the hourly rates  of loading/unloading = $ m   = $100

The hourly rates  of packing/unpacking = $ n   = $90

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

the diver is 33 feet below the surface.

step-by-step explanation:

hope this