A marching band is arranged in rows of 7 the first row has 3 band members and each row after the first has 2 more band members than the row before it write a rule for the number of band members in the nth row. Then find the total number of band members.

= 1+2n and 63

Step-by-step explanation:

the question belongs to arithmetic sequence and can be determined by the formula

= a1 + d (n-1)

Let " " represents the number of band members in the nth row

and 'd' represents the common difference.( as stated each row  has 2 more band members than the row before it)

therefore, d=2

'a1' represents first row that has three members. So, a1 = 3

->Rule for nth term will be:

= 3 + 2(n-1)

= 3 + 2n -2

= 1+2n

-> In order to find total number of band members ''

Let represent total number in n rows

We'll use the formula, i.e  = n/1 ( +  )

where, n is the number of terms, is the first term and is the last term

So,

n=7

= 1 + 2(7)= 15

=> = 7/2 (3 + 15)

= 63

The total number of band members are 63

the answer is d. 75%

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: