John has 48 square centimeter tiles he wants to use to
create a mosaic. He wants the mosaic to be rectangular
with a length that is 2 centimeters longer than the width.
Which equation could John solve to find w, the greatest
width in centimeters he can use for the mosaic?
ww-2) = 48
w(w + 2) = 48
2w(w - 2) = 48
2w(w + 2) = 48

363 square inches

step-by-step explanation:

surface area of a pyramid is b + 1/2ph

b is the area of the base: 11 x 11 = 121

p is the perimeter of the base: 11 + 11 + 11 + 11 = 44

h is the height of the pyramid: 11

121 + 1/2(44)(11)

121 + 242

363

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

mississippi is the answer

i hope i rawr xd