A six-sided number cube is rolled twice.
What is the probability that the first roll is an even number and the second roll is a number greater than 4

1/6

Step-by-step explanation:

There are 6 numbers on a dice

1,2,3,4,5,6

the even numbers are 2,4,6

so there are 3/6 chance of getting an even number

3/6=1/2

5 and 6 are the two numbers greater than 4

so there are 2/6 chance of getting a number greater than 4

2/6=1/3

So for both to happen chance = 1/2 × 1/3

 = 1/6

i think it would be c

mark brainliest if im right

step-by-step explanation: