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Mathematics, 09.04.2020 21:09 nick974

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Factor completely 2x^4y^3 - 12x^3y^2 - 8x^2y

A.) 2x^2y(x^2y^2− 6xy − 4)
B.) 2(x^4y^3 − 6x^3y^2 − 4x^2y)
C.) 2y(x^4y^2− 6x^3y− 4x^2)
D.) Prime

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Factor completely 2x^4y^3 - 12x^3y^2 - 8x^2y

A.) 2x^2y(...
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