If one end of diameter of a circle x square +y square - 4x- 6y-12=0 is (2,-2) then find the cordinates of the other end and the length of the diameter

ans = (2, 8) and 10 units

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

x=0

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

“ a line segment that has the endpoints on the circle and passes through the midpoint is called the diameter. the diameter is twice the size of the radius. a line segment that has its endpoints on the circular border but does not pass through the midpoint is called a chord. a circle is the same as 360 small circle up the number 0 . i hope this .