Which statement regarding polynomials and their zeros is true?
1) Ax) = (x2 - 1)(x+ a) has zeros of 1 and-a, only.
2) Ax) = x - ax? + 16x – 16a has zeros of 4 and a, only.
3) Ax) = (x2 +25)(x+ a) has zeros of +5 and-a.
4) f(x) = x -ax? - 9x + 9a has zeros of +3 and a.

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

x=-2

step-by-step explanation:

i began by flipping the problem to give me x= on the left (keeps it clearer for me).   so my problem simply became 10x-3=4x-6.  

1)   subtract 4x from the right side, which equals 0.   you do the same to the left of the equal as the right; therefore, subtract 4x from 10x, leaving 6x on the left.

              10x-3=4x-6   :   4x-4x on the right leaves only the -6        

2)             6x-3= 0-6 :    

                6x+3=   -6

3) divide

idk what your asking for but the sum equals 13