Mathematics, 10.04.2020 12:43 Jana1517
Boiling water, at 100 degrees Celsius, is placed in a freezer at 0 degrees Celsius. The temperature of the water is 50 degrees Celsius after 24 minutes. Find the temperature of the water to the nearest hundredth after 96 minutes
Answers: 3
![[T(t) - T_{a}] = [T(0) - T_{a}] e^{-kt}](/tpl/images/0593/6852/2d78e.png)
----> Temperature of the water at time 24 minutes
----> Temperature of the water at time 96 minutes![[50 - 0] = [100 - 0}] e^{-k(24)}](/tpl/images/0593/6852/1428e.png)
(Temperature of the water at time 96 minutes)![[T_9_6 - T_{a}] = [T(0) - T_{a}] e^{-kt}](/tpl/images/0593/6852/79c50.png)
![[T_9_6 - 0] = [100 - 0] e^{-0.02888*96}](/tpl/images/0593/6852/b6251.png)
![T_9_6= [100] e^{-0.02888*96}](/tpl/images/0593/6852/8702e.png)
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Boiling water, at 100 degrees Celsius, is placed in a freezer at 0 degrees Celsius. The temperature...
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