A hyperbola centered at the origin has a vertex at (0,−40) and a focus at (0, 41).

Which are the equations of the asymptotes?

y = +_ 9/40

y = ±x40/41

y = ±x41/40

y = ±x40/9

2,600 divided by 80 = 32.5

step-by-step explanation:

what is all that apply?

a

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.