Use the work shown below to write the equation for a line that has a slope of Negative two-fifths and passes through (15, –2).

y = mx + b

1. Substitute the known values: negative 2 = negative two-fifths (15) + b. 2. Solve for b: negative 2 = negative 6 + b. b = 4.

What is the equation of the line in slope-intercept form?
Negative 2 = negative two-fifths x + 4
y = negative two-fifths (15) + 4
y = negative two-fifths x minus 4
y = negative two-fifths x + 4

57 732

step-by-step explanation:

i dont really.know

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.