A polynomial f of degree 3 that has zeros at -1 and 2 and has f(0) =3

f(x) = (x+1)(x-2)(x-3/2)

Step-by-step explanation:

hello :

an polynomial f of degree 3 is : f(x) = (x+1)(x-2)(x-a)

f(0) =3   means : (0+1)(0-2)(0-a) =3

so : 2a=3     a=3/2

f(x) = (x+1)(x-2)(x-3/2)

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl