A shelf has 4 blue pairs of pants, 2 black pairs of pants, 1 white pair of pants, and 3 tan pairs of pants. You randomly choose a pair of pants from the shelf. What is the probability of choosing a pair of pants that is not white?

9/10 probability

Step-by-step explanation:

What you're trying to figure out is how likely the pants you select to not be white. The formula for this sort of thing is:

(How many things fit the probability you're looking for)/(However may there are of the thing total)

Because 9 of the clothes are not white, and would therefore fit the probability you're looking for, you would put 9 at the top (4 blue, 2 black, 3 tan)

Lastly, add all the clothes up total and put that number on the bottom (4 + 2 + 1 + 3 = 10)

Therefore, the answer is 9/10

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.