After the closing of the mill, the town of Sawyerville experienced a decline in its population.
The relationship between the elapsed time, ttt, in years, since the closing of the mill, and the town's population, P(t)P(t)P, left parenthesis, t, right parenthesis, is modeled by the following function.
P(t)=12,000⋅2−t15
In how many years will Sawyerville's population be 9000?
Round your answer, if necessary, to the nearest hundredth.

Step-by-step explanation:

P(t) = 12,000 (2)^(-t/15)

9,000 = 12,000 (2)^(-t/15)

0.75 = 2^(-t/15)

ln(0.75) = ln(2^(-t/15))

ln(0.75) = (-t/15) ln(2)

-15 ln(0.75) / ln(2) = t

t = 6.23

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)