Which statement is true concerning the vertex and axis of symmetry of h(x)=−2x2+8x?

the vertex is at (2, 8) and the axis of symmetry is x = 2

Step-by-step explanation:

In h(x)=−2x2+8x please use the symbol " ^ " to indicate exponentiation:

h(x)=−2x^2+8x      

This is a quadratic equation with coefficients a = -2, b = 8 and c = 0.

The axis of symmetry equation is x = -b/ (2a).

                                                                                                -8

Here, with a = -2 and b = 8, the axis of symmetry is   x = = 2

                                                                                               2(-2)

To find the y-coordinate of the vertex, substitute 2 for x in h(x)=−2x^2+8x, obtaining

h(2) = -2(2)^2 + 8(2) = -2(4) + 16 = 8

In summary, the vertex is at (2, 8) and the axis of symmetry is x = 2.

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555.99.

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