Two different gasohol mixtures are available. One contains 5% alcohol and the other 12% alcohol. How much of each should be mixed to obtain 1000 gal of gasohol containing 10% alcohol?

The volume of gasohol mixture 1 that should be taken is 285.7 gal and mixture 2 is 714.3 gal

Explanation:

Let the volume of each gasohol mixture 1 be x gal

Let the volume of gasohol mixture 2 be y gal

Gasohol mixture 1 = 5% alcohol

Gasohol mixture 2 = 12 %

According to the question:

and

Multiplying equation 1 with 0.12 we get:

0.12x + 0.12y = 120

On solving both the equations we  get:

0.12x + 0.12y = 120

0.05x + 0.12y = 100

___________________

0.07x = 20

x = 285.7 gal

Substituting x = 285.7 in equation 1:

285.7 + y = 1000

y = 714.3

Therefore, the volume of gasohol mixture 1 that should be taken is 285.7 gal and mixture 2 is 714.3 gal

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743