Among 20 olden hamster litters recorded, there was a sample mean of baby hamsters, with a sample standard deviation of. Create a 97.5 confidence interval for the mean number of baby hamsters per liter

So on this case the 97.5% confidence interval would be given by (6.360;9.080)    

Step-by-step explanation:

For this case we assume the deviation given as s =2.5 and the mean

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

represent the sample mean

population mean (variable of interest)

s=2.5 represent the sample standard deviation

n=20 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

  (1)

In order to calculate the critical value we need to find first the degrees of freedom, given by:

Since the Confidence is 0.975 or 97.5%, the value of and , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.0125,19)".And we see that

Now we have everything in order to replace into formula (1):

So on this case the 97.5% confidence interval would be given by (6.360;9.080)    

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

i think u have 12 apples sorry again i don't really know if it correct i'm just tryna hrlp people out.