Two cars left the city for a suburb, 480 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the speed of the other, and that is why it arrived at the suburb 2 hour earlier than the other car. Find the speeds of both cars.

Time taken by car A = 6 hr and time taken by car B is 8 hours

Explanation:

Given:

Distance, d = 480 km

Let x be the time taken by B to reach the destination:

So,

Time taken by car A to reach the destination = x -2

We know:

Distance = speed X time

speed =

On substituting the value we get:

Speed of car A =

Speed of car B =

Since car A travelled 20 km/hr faster than the car B, the equation becomes:

Multiplying both sides by (x - 2) we get:

Therefore, time taken by car A = x - 2

                                                   = 8 - 2 hr

                                                   = 6 hr

Time taken by car B = 8 hr

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6