Drag the tiles to the correct boxes to complete the pairs. Match each word problem to its solution. Seven more than 3 times a number is 49. What is the number? Hillary's age is 3 years greater than times Lily's age. If Hillary is 19 years old, how old is Lily? Twice a number decreased by 20 is 50. What is the number? Claret purchased two handbags and a wallet. The cost of each handbag was $10 more than the wallet. If she spent a total of $60 for the two handbags, what is the cost of the wallet? 35 arrowBoth 20 arrowBoth 14 arrowBoth 24 arrowBoth

(A) The number is 14

(B) Lily is 16 years old

(C)The number is 35

(D) The wallet cost $20

Step-by-step explanation: (A) Let the number be a. Three times the number is equal to 3 times a, or 3a. Seven more than 3a equals 49, that means

7 + 3a = 49

Subtract 7 from both sides of the equation

3a = 42

Divide both sides of the equation by 3

a = 14

The number is 14

(B) Let Hillary's age be h and Lily's age be l, so if Hillary's age is 3 years greater than Lily's age, then we have

h = 3 + l

Then if Hillary's age is now given as 19, the equation becomes

19 = 3 + l

Subtract 3 from both sides of the equation

16 = l

Lily's age is 16

(C) Let the number be x, and so twice the number becomes 2 times x which is 2x. Twice the number decreased by 20 is 50, becomes

2x - 20 = 50

Add 20 to both sides of the equation

2x = 70

Divide both sides of the equation by 2

x = 35

The number is 35

(D) Let each handbag be represented by b and each wallet be represented by w. The cost of each handbag is 10 more than the wallet, so if the wallet cost w, then the handbag would cost w + 10. This can be expressed as

h = w + 10

If she spent a total of 60 for the 2 handbags, then each handbag would cost 60 ÷ 2 which equals 30 per handbag. Substituting for the known value we now have,

30 = w + 10

Subtract 10 from both sides of the equation

20 = w

The cost of a wallet is $20