The population of Marshville is loosing 20% of their population of frogs per year. There are currently 900 frogs in Marshville. How many frogs will there be in 5 years?

There will be 262 frogs in 5 years

Step-by-step explanation:

The population of Marshville can be modeled by the following equation.

In which P(t) is the population after t years, P(0) is the initial population, and r is how much the population decreases by year.

In this problem, we have that:

So

How many frogs will there be in 5 years?

This is P(5)

There will be 262 frogs in 5 years

295 frogs

Step-by-step explanation:

The Population of Marshville is loosing 20% of their population of frogs per year.

This means the value of the next year is 80% of the previous year.

This is an example of a geometric series in which the common ratio =80%

The nth term of a geometric series is given as:

Where a=First Term, r=Common Ratio, n=Number of Terms

In this case.

a=900, r=80%=0.8, n=6 (After 5 years)

In 5 years time, there will be 295 frogs in Marshville.