The data in the table below represents the pressure of the gas as the temperature changes. plot a graph of this data. draw a trend line and calculate its slope. how are the variables related? what will the pressure of the gas be at 0°c? the data is: . temp(c): 10, 25, 40, 55, 80. pressure (torr): 723, 763, 800, 845, 900.

The correct answer is:

The slope of the trend line is 2.55; as the temperature increases, the gas pressure increases as well.

Explanation:

The graph is attached. Using a graphing calculator to plot the data and run the regression, we get the figure attached. The value for a, the slope, is 2.55, and the value of b, the y-intercept, is 699.01. The line increases; this means as the x-value, the temperature, increases, so does the y-value, the pressure.

The variables are linearly related.

Slope of given data line is 2.5522

The pressure of the gas be at 0°C is 699.01 torr.

Step-by-step explanation:

Given:  The data in the table below represents the pressure of the gas as the temperature changes.

We have to plot the graph of the given data .

Consider the given Table,

On x - axis , we represents temperature of gas in °C and on y- axis , we represents the pressure of gas in torr.

We know plot the given data.

We obtained the equation of line as y = 2.5522 x + 699.01

Thus, The equation of line is given as y = mx + b , where m is slope and b is y intercept

Thus, Slope of given data line is 2.5522

and to calculate the pressure of the gas at 0°C is given by putting x = 0, we get

y = 699.01

Thus, The pressure of the gas be at 0°C is 699.01 torr.

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square