What are the solutions of the equation x4 + 6x2 + 5 = 0? Use u substitution to solve.
x = i and x = iStartRoot 5 EndRoot
x = plus-or-minus i and x = plus-or-minus iStartRoot 5 EndRoot
x = plus-or-minus StartRoot negative 1 EndRoot and x = plus-or-minus StartRoot negative 5 EndRoot
x = plus-or-minus Negative 1 and x = plus-or-minus -StartRoot 5 EndRoot

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w