Let F=xi+(x+y)j+(x−y+z)k. Let the line l be x=t−1, y=2−3t, z=2+5t. (a) Find a point P=(x0,y0,z0) where F is parallel to l. P= equation editorEquation Editor Find a point Q=(x1,y1,z1) at which F and l are perpendicular. Q= equation editorEquation Editor Give an equation for the set of all points at which F and l are perpendicular. equation: equation editorEquation Editor

l' jhl jje f id bid b e iueb v jhdvb vh ei uf djbduv evb                                                                                                                                   8gfdgsfhjk.,l/ uh   dv eb b                            

using the formula for pythagorean theorem (a2+b2=c2)(the twos are exponents), and knowing that you have b squared and c squared, just reverse it. 26 squared minus 10 squared equals c squared. 26 squared is 676 and 10 squared is 100. you get 576, then use your square roots to undo the squared numbers to get 24.