What is the area of the regular pentagon below?
2.4 yd
3.5 yd
O
O
A. 42.0 yd
B . 30.6 yd2
OC. 8.4 yd

21yd^2

Step-by-step explanation:

join the centre to all the vertex,

since this figure is of regular pentagon, it's will form 5 equal triangle of equal area!

now area of one such triangle is

1/2 ×base ×height

=1/2 ×3.5x2.4 (yd^2)

=4.2 yd^2

now the pentagon is sum of 5 such equal triangle,so it's are will be

5×4.2 (yd^2)

=21 yd^2

✌️:)

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.