A hypothesis test was conducted to investigate whether the population proportion of students at a certain college who went to the movie theater last weekend is greater than 0.2. A random sample of 100 students at this college resulted in a test statistic of 2.25. Assuming all conditions for inference were met, which of the following is closest to the pp-value of the test?

A. 0.0061
B. 0.0122
C. 0.0244
D. 0.9756
E. 0.9878

B. 0.0122

Step-by-step explanation:

According to the given data the claim is:

"Proportion of students who went to the movie theater last weekend is greater than 0.2"

Since, the word "greater than" is used in the claim, this claim will be our alternate hypothesis and the hypothesis test will be a one-tailed test i.e. Right tailed test because of the word "greater than".

We are given that the hypothesis test was conducted for a random sample of 100 students and it yielded a z-value of 2.25. We have to find the p-value associated with this z-score

So, we have to find p-value corresponding to z-score of 2.25 and Right Tailed Test. We have to use z-table for this purpose and find the probability of z score being greater than 2.25. From the z-table this value comes out to be:

p-value = 0.0122

Therefore, option B gives the correct answer.

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step-by-step explanation:

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i know the way

and

idk

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.