The cone pictured has a surface area of _ square meters. (Use 3.14 for π .)

Step-by-step explanation:

r is the radius

h is the height

l is the slant height

The area of the curved (lateral) surface of a cone = πrl

To begin with we need to find slant height of the cone, which is determined by using Pythagoras, since the cross section is a right triangle.

l² = h² + r²

l² = 11² + 5²

l² = 121 + 25

l = √146

l = 12.08cm

And the total surface area of the cone is:

SA = πr²+ πrl

SA = π · r · (r + l)

SA = π · 5 · (5 + 12.08)

SA = 3.14 * 5 * 17.08

SA = 268.156 cm²

Therefore, the total surface area of the cone is 268.156 cm2

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18