Find the 76th term of the arithmetic sequence 16, 14, 12, ...
I need help pls

Step-by-step explanation:

The answer is -134

Step-by-step explanation: Common Difference:

d=a_2-a_1=(14)-(16)=-2d=a2−a1=(14)−(16)=−2

a_n=a_1+(n-1)dan=a1+(n−1)d

\text{76th term:}76th term:

a_{76}=16 + (76-1)(-2)a76=16+(76−1)(−2)

a_{76}=16 + (75)(-2)a76=16+(75)(−2)

a_{76}=-134a76=−134

the 4th choice is the correct one

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)