The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. Assume that the population standard deviation is 2.52.5 kWh. The mean electricity usage per family was found to be 1616 kWh per day for a sample of 33943394 families. Construct the 98%98% confidence interval for the mean usage of electricity. Round your answers to one decimal place.

(15.9,16.1) is the required 98% confidence interval for mean usage of electricity.

Step-by-step explanation:

We are given the following in the question:

Sample mean, = 16 kWh

Sample size, n = 3394

Alpha, α = 0.02

Population standard deviation, σ = 2.5 kWh

98% Confidence interval:

Putting the values, we get,

(15.9,16.1) is the required 98% confidence interval for mean usage of electricity.

answer is x<

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet