The population mean annual salary for environmental compliance specialists is about $60 comma 500. A random sample of 32 specialists is drawn from this population. What is the probability that the mean salary of the sample is less than $57 comma 500? Assume sigmaequals$6 comma 400.

0.004 is the probability that the mean salary of the sample is less than $57,500.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,500

Standard Deviation, σ = $6,400

Sample size, n  = 32

Formula:

Standard error due to sampling =

P(mean salary of the sample is less than $57,500)

Calculation the value from standard normal z table, we have,  

0.004 is the probability that the mean salary of the sample is less than $57,500.

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

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step-by-step explanation: