At a track meet with 200 participants, 45 participate in jumping event, 1/3 of these jumpers are female, and 1/2 of the the total participants are female. What is the probability that a participant chosen at random is a jumper, given that the person is a female?

The correct answer is 0.15.

Step-by-step explanation:

Total number of participants for the track meet = 200

Number of females among the participants = × 200 = 100

Number of persons participate in the jumping event = 45

Number of females among these jumper = × 45 = 15

Therefore the number of female jumpers are 15 out of the 100 female participants for the track meet.

Therefore the probability that a participant chosen at random is a jumper, given that the person is a female is = 0.15

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.