You have two lightbulbs for a particular lamp. Let X 5 the lifetime of the first bulb and Y 5 the lifetime of the second bulb (both in 1000s of hours). Suppose that X and Y are independent and that each has an exponential distribution with parameter l 5 1. a. What is the joint pdf of X and Y? b. What is the probability that each bulb lasts at most 1000 hours (i. e., X # 1 and Y # 1)?

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

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