The number of pits in a corroded steel coupon follows a Poisson distribution with a mean of 6 pits per cm2. Let X represent the number of pits in a 1 cm2 area. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.

Find P(X = 2).

P(X=2)=0.0446

Step-by-step explanation:

If X follows a Poisson distribution, the probability p to have x pits in 1 cm2 is calculated as:

Where m is the mean of pits per cm2, so, replacing m by 6 pits per cm2, we get that the probability is equal to:

Now, the probability P(x=2) that there are 2 pits in a 1 cm2 is calculated as:

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide