4. At a local university 54.3% of incoming first-year students have computers. If 3 students are selected at random, and the following probabilities. a. None have computers. b. At least one has a computer. c. All have computers.

a) 0.0954

b) 0.9045

c) 0.1601

Step-by-step explanation:

We are given the following information:

We treat first-year students having computers as a success.

P(first-year students have computers) = 54.3% = 0.543

Then the number of first year students follows a binomial distribution, where

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3

a) P(None have computers)

b) P(At least one has a computer)

c) P(All have computers)

d 600 because 15*10*2=300

300+300=600

step-by-step explanation: