The average amount of money individuals pay when buying a used car is $7,310 and the standard deviation is $1,640. Assume the amount of money individuals pay when buying a used car is normally distributed. Find the probability that for a sample of 35 individuals that purchase a used car, they will pay an average (Show your work to receive credit)

(a) The probability that for a sample of 35 individuals that purchase a used car will pay an average between $6820 to $7880 is 0.9120.

(b) The probability that for a sample of 35 individuals that purchase a used car will pay an average of more than $ 7140 is 0.7258.

Step-by-step explanation:

Let X =  amount of money individuals pay when buying a used car.

The random variable X is Normally distributed with mean μ = $7310 and standard deviation σ = $1640.

A sample of n = 35 individuals who purchase a used car is selected.

We need to compute the probability of:

(a) Between $6820 to $7880

(b) More then $7140.

(a)

Compute the probability that for a sample of 35 individuals that purchase a used car will pay an average between $6820 to $7880 as follows:

*Use a z-table for the probability.

Thus, the probability that for a sample of 35 individuals that purchase a used car will pay an average between $6820 to $7880 is 0.9120.

(b)

Compute the  probability that for a sample of 35 individuals that purchase a used car will pay an average of more than $ 7140 as follows:

*Use a z-table for the probability.

Thus, the probability that for a sample of 35 individuals that purchase a used car will pay an average of more than $ 7140 is 0.7258.

dont think so

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.