There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, and 188 who have taken courses in both calculus and discrete mathematics. How many students have taken a course in either calculus or discrete mathematics

Number of people choose either calculus or discrete math is 369

Given that;

Number of people choose calculus = 345  

Number of people choose discrete math = 212  

Number of people choose Calculus and discrete math = 188

Find:

Number of people choose either calculus or discrete math

Computation:

Number of people choose either calculus or discrete math = Number of people choose calculus + Number of people choose discrete math - Number of people choose Calculus and discrete math

Number of people choose either calculus or discrete math =  345 + 212 - 188

Number of people choose either calculus or discrete math = 369

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369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

188 who have taken courses in both calculus and discrete mathematics.

This means that

212 who have taken a course in discrete mathematics

This means that

345 students at a college who have taken a course in calculus

This means that

How many students have taken a course in either calculus or discrete mathematics

369 students have taken a course in either calculus or discrete mathematics

i think is g(1)=-1.

hope that i can