You are filling baskets using 18 green eggs, 36 red eggs and 54 blue eggs. What is the greatest number of baskets that you can fill so that the baskets are identical and there are no eggs left over

18 baskets

Explanation:

Let n = number of baskets that can be filled so that the baskets are identical and there are no eggs left over

Each color of eggs divisible by n must be equal to each other

18 green eggs, 36 red eggs and 54 blue eggs

18/n = 36/n = 54/n

Using logic and plug in method

All of them are divisible by 2, 3, 6, 9 and 18

The greatest is 18.

18 is therefore the greatest number of baskets that you can fill so that the baskets are identical and there are no eggs left over.

Another method is to use HCF among the 18 green eggs, 36 red eggs and 54 blue eggs.

This means that each basket will contain 1 green egg, 2 red eggs and 3 blue eggs.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

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