Four congruent circular holes with a diameter of 2 in. were punched out of a rectangular piece of paper.

A rectangle with length 11 inches and width 8.5 inches. 4 circular holes with a diameter of 2 inches are cut out of the rectangle.

What is the area of the paper that is left? Use 3.14 for Pi.
A) 80.94 inches squared
B) 90.36 inches squared
C) 93.50 inches squared
D) 106.06 inches squared

80.94

Step-by-step explanation:

Somebody told me it. I don't know if it is right or wrong so don't get mad.

A: 80.94

Step-by-step explanation:

For this case we first calculate the area of the complete rectangle.

 We have then:

 A1 = (8.5) * (11)

 A1 = 93.5

 Then, we calculate the area of each circle:

 A2 = pi * r ^ 2

 A2 = (3.14) * (2/2) ^ 2

 A2 = 3.14

 The total area is given by:

 A = A1 - 4 * A2

 A = 93.5 - 4 * (3.14)

 A = 80.94 in ^ 2

answer: idk

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.