A new technology for the production of integrated circuits is being mastered. The technology will be rejected if the percentage of the defective integrated circuits exceeds 2%. How many integrated circuits have to be checked to make sure that the technology gives a sufficiently small amount of defects with a probability of 0.5% if the actual probability is p = 0.04? Use a = 0.05. Use the z-values rounded to two decimal places to obtain the answer. n = the absolute tolerance is +/-1

Following are the calculation for the sample size:

Given:

To find:

sample size=?

Solution:

The formula for the sample size:

Putting the value in the above-given formula:

Therefore, the final answer is "756.41"

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5901

Step-by-step explanation:

The margin of error is the critical value times the standard error.

ME = CV × SE

For α = 0.05, the critical value is z = 1.96.

The standard error of a proportion is √(pq/n).  Given p = 0.04, then q = 1−p = 0.96.

The margin of error is 0.5% or 0.005.

Plugging in:

0.005 = 1.96 √(0.04 × 0.96 / n)

n ≈ 5901

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !