Given that x and y are positive integers and (x·2)+x(2^2)+(y·2^3)+(y·2^4)=42, what is the value of xy?

pls helpp

The numbers are x = 3 and y = 1. Therefore the value of xy is 3.

Step-by-step explanation:

In order to calculate the numbers we will simplify the equation, this is done bellow:

2*x + x(2^2) + (y*2^3) + (y*2^4) = 42

2*x + 4*x + 8*y + 16*y = 42

6*x + 24*y = 42

We can divide the whole equation by 6, so we have:

x + 4*y = 7

The only possible combination of numbers that are positive and integers that will make the equation valid is x = 3 and y = 1. Therefore he value of xy is 3.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

step-by-step explanation:

cats