Given that sin 0 = 12/13 what is cos 0 ?
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Step-by-step explanation:

Given

sin theta = 12/ 13 = p/h

Therefore p = 12 , h = 13 and b = ?

We know by using Pythagoras theorem

b² = h² - p²

b² = 13² - 12²

b² = 169 - 144

b² = 25

b² = 5²

Therefore b = 5

So now

cos theta

= b/h

= 5 / 13

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